Duh. Simple process..
Ksp = [Ca][F]^2
[Ca] = x = [F] / 2
So, 3.8 x 10^-11 = x^3 / 4. Solve for x. This will give you the M of the solution and, assuming 1L, the number of moles of CaF2 that can dissolve.
Multiply by the molar mass of CaF2 to find the grams that dissolved and you have your answer in g/L
Looks kind of like this :dunno:
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1. Ksp = [Ca][F]^2
[Ca] = x = [F] / 2
So, 3.8 x 10^-11 = x^3 / 4. Solve for x. This will give you the M of the solution and, assuming 1L, the number of moles of CaF2 that can dissolve.
Multiply by the molar mass of CaF2 to find the grams that dissolved and you have your answer in g/L
3 years ago